Safe Haskell | Safe-Inferred |
---|---|
Language | Haskell2010 |
Control.Monad.IO.Unlift
Description
Please see the README.md file for information on using this package at https://www.stackage.org/package/unliftio-core.
Synopsis
- class MonadIO m => MonadUnliftIO m where
- withRunInIO :: ((forall a. m a -> IO a) -> IO b) -> m b
- newtype UnliftIO m = UnliftIO {}
- askUnliftIO :: MonadUnliftIO m => m (UnliftIO m)
- askRunInIO :: MonadUnliftIO m => m (m a -> IO a)
- withUnliftIO :: MonadUnliftIO m => (UnliftIO m -> IO a) -> m a
- toIO :: MonadUnliftIO m => m a -> m (IO a)
- wrappedWithRunInIO :: MonadUnliftIO n => (n b -> m b) -> (forall a. m a -> n a) -> ((forall a. m a -> IO a) -> IO b) -> m b
- class Monad m => MonadIO (m :: Type -> Type) where
Documentation
class MonadIO m => MonadUnliftIO m where Source #
Monads which allow their actions to be run in IO
.
While MonadIO
allows an IO
action to be lifted into another
monad, this class captures the opposite concept: allowing you to
capture the monadic context. Note that, in order to meet the laws
given below, the intuition is that a monad must have no monadic
state, but may have monadic context. This essentially limits
MonadUnliftIO
to ReaderT
and IdentityT
transformers on top of
IO
.
Laws. For any value u
returned by askUnliftIO
, it must meet the
monad transformer laws as reformulated for MonadUnliftIO
:
unliftIO u . return = return
unliftIO u (m >>= f) = unliftIO u m >>= unliftIO u . f
Instances of MonadUnliftIO
must also satisfy the idempotency law:
askUnliftIO >>= \u -> (liftIO . unliftIO u) m = m
This law showcases two properties. First, askUnliftIO
doesn't change
the monadic context, and second, liftIO . unliftIO u
is equivalent to
id
IF called in the same monadic context as askUnliftIO
.
Since: 0.1.0.0
Methods
withRunInIO :: ((forall a. m a -> IO a) -> IO b) -> m b Source #
Convenience function for capturing the monadic context and running an IO
action with a runner function. The runner function is used to run a monadic
action m
in IO
.
Since: 0.1.0.0
Instances
MonadUnliftIO IO Source # | |
Defined in Control.Monad.IO.Unlift | |
MonadUnliftIO m => MonadUnliftIO (IdentityT m) Source # | |
Defined in Control.Monad.IO.Unlift | |
MonadUnliftIO m => MonadUnliftIO (ReaderT r m) Source # | |
Defined in Control.Monad.IO.Unlift |
The ability to run any monadic action m a
as IO a
.
This is more precisely a natural transformation. We need to new
datatype (instead of simply using a forall
) due to lack of
support in GHC for impredicative types.
Since: 0.1.0.0
askUnliftIO :: MonadUnliftIO m => m (UnliftIO m) Source #
Capture the current monadic context, providing the ability to
run monadic actions in IO
.
See UnliftIO
for an explanation of why we need a helper
datatype here.
Prior to version 0.2.0.0 of this library, this was a method in the
MonadUnliftIO
type class. It was moved out due to
https://github.com/fpco/unliftio/issues/55.
Since: 0.1.0.0
askRunInIO :: MonadUnliftIO m => m (m a -> IO a) Source #
Same as askUnliftIO
, but returns a monomorphic function
instead of a polymorphic newtype wrapper. If you only need to apply
the transformation on one concrete type, this function can be more
convenient.
Since: 0.1.0.0
withUnliftIO :: MonadUnliftIO m => (UnliftIO m -> IO a) -> m a Source #
Convenience function for capturing the monadic context and running
an IO
action. The UnliftIO
newtype wrapper is rarely needed, so
prefer withRunInIO
to this function.
Since: 0.1.0.0
toIO :: MonadUnliftIO m => m a -> m (IO a) Source #
Convert an action in m
to an action in IO
.
Since: 0.1.0.0
Arguments
:: MonadUnliftIO n | |
=> (n b -> m b) | The wrapper, for instance |
-> (forall a. m a -> n a) | The inverse, for instance |
-> ((forall a. m a -> IO a) -> IO b) | The actual function to invoke |
-> m b |
A helper function for implementing MonadUnliftIO
instances.
Useful for the common case where you want to simply delegate to the
underlying transformer.
Example
newtype AppT m a = AppT { unAppT :: ReaderT Int (ResourceT m) a } deriving (Functor, Applicative, Monad, MonadIO) -- Unfortunately, deriving MonadUnliftIO does not work. instance MonadUnliftIO m => MonadUnliftIO (AppT m) where withRunInIO = wrappedWithRunInIO AppT unAppT
Since: 0.1.2.0
class Monad m => MonadIO (m :: Type -> Type) where Source #
Monads in which IO
computations may be embedded.
Any monad built by applying a sequence of monad transformers to the
IO
monad will be an instance of this class.
Instances should satisfy the following laws, which state that liftIO
is a transformer of monads:
Methods
liftIO :: IO a -> m a Source #
Lift a computation from the IO
monad.
This allows us to run IO computations in any monadic stack, so long as it supports these kinds of operations
(i.e. IO
is the base monad for the stack).
Example
import Control.Monad.Trans.State -- from the "transformers" library printState :: Show s => StateT s IO () printState = do state <- get liftIO $ print state
Had we omitted
, we would have ended up with this error:liftIO
• Couldn't match type ‘IO’ with ‘StateT s IO’ Expected type: StateT s IO () Actual type: IO ()
The important part here is the mismatch between StateT s IO ()
and
.IO
()
Luckily, we know of a function that takes an
and returns an IO
a(m a)
:
,
enabling us to run the program and see the expected results:liftIO
> evalStateT printState "hello" "hello" > evalStateT printState 3 3